16=(x^2-9)

Solution for 16=(x^2-9) equation:

16=(x^2-9)

We move all terms to the left:

16-((x^2-9))=0


We calculate terms in parentheses: -((x^2-9)), so:

(x^2-9)

We get rid of parentheses

x^2-9

Back to the equation:

-(x^2-9)


We get rid of parentheses

-x^2+9+16=0

We add all the numbers together, and all the variables

-1x^2+25=0

a = -1; b = 0; c = +25;
Δ = b2-4ac
Δ = 02-4·(-1)·25
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10}{2*-1}=\frac{-10}{-2}
=+5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10}{2*-1}=\frac{10}{-2}
=-5
$